05-11-2014, 05:24 AM
Hi Guys
Just checking if this rule is correct?
Currently worded as 1.5 times the drag (rounded up) of an a/c's 2G turn/transition drag. This means that a 1G turn causes MORE drag than a 2G turn!
Should it not be less drag for less G? Should the calculation be the 2G drag DIVIDED by 1.5, instead of multiplied by 1.5
In the example given the calculation for 2x 1G turns is:
1.5x2=3
2x3=6 drag for 2 1G turns
Should the calculation for 2x 1G turns actually be this:
2 divided by 1.5 = 1.33
1.33 x 2 = 2.66 rounded up to 3
So therefore 2 1G turns would incur a total of 3 drag (which is less than 2 2G turns at 4 drag) instead of 6 drag (which is more than 2 2G turns, which is my point really..........surely the drag should be less for a 1G turn)
The problem comes with executing only 1 turn at 1G, because you end up with 1.33 drag, which if rounded up is the same cost as a 2G turn? Can we have 0.5 drag amounts? So a 1G turn would cost 1.5 drag versus a 2G turn costing 2 drag
All of theses are based on the SE5A in the 0 - 2.95 altitude band, as per the example
Just a thought?
Cheers
Drew
Just checking if this rule is correct?
Currently worded as 1.5 times the drag (rounded up) of an a/c's 2G turn/transition drag. This means that a 1G turn causes MORE drag than a 2G turn!
Should it not be less drag for less G? Should the calculation be the 2G drag DIVIDED by 1.5, instead of multiplied by 1.5
In the example given the calculation for 2x 1G turns is:
1.5x2=3
2x3=6 drag for 2 1G turns
Should the calculation for 2x 1G turns actually be this:
2 divided by 1.5 = 1.33
1.33 x 2 = 2.66 rounded up to 3
So therefore 2 1G turns would incur a total of 3 drag (which is less than 2 2G turns at 4 drag) instead of 6 drag (which is more than 2 2G turns, which is my point really..........surely the drag should be less for a 1G turn)
The problem comes with executing only 1 turn at 1G, because you end up with 1.33 drag, which if rounded up is the same cost as a 2G turn? Can we have 0.5 drag amounts? So a 1G turn would cost 1.5 drag versus a 2G turn costing 2 drag
All of theses are based on the SE5A in the 0 - 2.95 altitude band, as per the example
Just a thought?
Cheers
Drew